无限传奇之废墟战神

+1)(t+1)=1/[2(t+1)]+t/(t?

?

+t?

?

+t+1)

d?

?

y/dx?

?

=(dy'/dt)/(dx/dt)={-1/[2(t+1)?

?

]+[(t?

?

+t?

?

+t+1)-t(3t?

?

+2t+1)]/(t?

?

+t?

?

+t+1)?

?

}/(2t+2)

={-1/[2(t+1)?

?

]+[(t?

?

+1)(t+1)-3(3t?

?
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